To solve the problem related to "小熊刷粉丝" (Little Bear Brushes Fans), we first need clear details of the problem (e.g., rules for gaining fans, constraints like coins/time, target to reach). However, based on common similar problems, here's a hypothetical example and solution to illustrate the approach: Little Bear wants to buy fans. Each purchase gives 100 fans, and the cost increases by 1 coin per purchase (1st:1 coin, 2nd:2 coins, ..., k-th:k coins). He has N coins. How many fans can he get?

Approach

The key is to find the maximum number of purchases (k) such that the sum of costs (1+2+...+k) ≤ N. The sum of the first k integers is S = k*(k+1)/2.

Steps:

1. Calculate the largest k where S ≤ N using the quadratic formula: k = floor( (sqrt(8*N + 1) -1)/2 )
2. The total fans are k *100 (since each purchase gives100 fans).

Example Calculation

If N=10 coins:

• S = k(k+1)/2 ≤ 10 → k=4 (sum=1+2+3+4=10) → fans=4100=400.

If N=7 coins:

• k=3 (sum=6 ≤7) → fans=3*100=300 (remaining coins=1, not enough for next purchase of cost 4).

Request for More Details

To provide an accurate solution, please share the full problem statement including:

• Rules for gaining fans (e.g., cost per purchase, growth rate, time constraints).
• Input parameters (e.g., coins, days, target fans).
• The exact question (e.g., max fans with given coins, days to reach target).

Once you provide these details, I can give a precise answer!

Answer: Please share the full problem details for a correct solution. For the hypothetical case above, the answer would be as per the example (e.g.,400 fans for N=10). But this depends on the actual problem rules. Let me know!
(If you have the original problem in Chinese, feel free to paste it—I can translate and solve it.)
\boxed{Need\ more\ details} (or replace with the correct answer once details are provided)